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#key#bitcoin#llm#win#fun#attack#odds#why#transaction#don

Discussion (48 Comments)Read Original on HackerNews

sunirabout 6 hours ago
I don't get it. That wasn't hard. What do I do with the key now that I have it?
gavmorabout 5 hours ago
Nothing much, since quantum supremacy will drive all coins to zero, but it is a biohazard.

Email it to me and I'll safely dispose of it for you at a responsible E-waste site.

kibwenabout 5 hours ago
Same here. I guess "xxxxxxxxxxxxxxxxxxxxxxxxxxxxx12345" made it easy for Satoshi to remember, though.
soperjabout 5 hours ago
Post it on here. We'll all help you out.
dudeinjapanabout 5 hours ago
The honest thing to do is to return the key you found to its owner Satoshi Nakamoto.
curiousObjectabout 4 hours ago
>At one spin per millisecond (faster than this app runs), you'd expect a hit roughly once per 1.7 × 10⁶² years — about 10⁵² times the current age of the universe. The heat death of the universe occurs first

Alright! Now there’s only the heat death of the universe standing between me and massive wealth? I like these odds.

gumgumpostabout 2 hours ago
Those are just the odds, but you randomly finding it in the next 10 minutes is a valid move in this universe. The silly low odds don't guarantee you won't find it.
meowfaceabout 4 hours ago
I'm not opposed to LLM-generated code at all, but the such obviously LLM-written README is annoying. The style is so easy to spot. At least try to figure out how to prompt it to not write so obviously like an LLM. (And no, I'm not even referring to the em dashes.)
futuneabout 4 hours ago
Why would you want LLM content to masquarade as non-LLM content? I think I'd rather have it be obvious if people are going to be using it anyway.
bpavukabout 4 hours ago
ignorance is bliss. all LLM text reads same-y. that way, we at least have an illusion that this is not a LLM
sunrunnerabout 5 hours ago
99% of gamblers quit before they win big. In this case, really big. I am going to be the 1%. Or should that be the 1.9e-71%.
ck45about 4 hours ago
You either win or you don’t, it’s 50:50
int32_64about 5 hours ago
A better project would be to take the exact key generation function at the time Satoshi started it and mine possible PRNG parameters.
amarantabout 5 hours ago
I dunno if I'm missing something, but I can't see the actual guessed key anywhere on the site?

So if I win, I won't be able to actually claim the Mooney's?

Hakkinabout 5 hours ago
The key shows up if you win, you can simulate it by adding ?devwin=1 to the URL.
amarantabout 5 hours ago
Oh. That makes sense I guess.

I don't think it'll ever show for reals

opengrassabout 5 hours ago
There's also the Large Bitcoin Collider. Last time coins were recovered was 9 years ago. https://lbc.cryptoguru.org/about
FajitaNachosabout 6 hours ago
I made a similar concept, but it wasn't self hosted. I never made the front page though! Congrats. Could you add a video of the experience to GitHub. Without that I wasn't willing to download and give it a go
CobrastanJorjiabout 5 hours ago
What's really fun is that, if you win and do anything about it, Bitcoin's value immediately crashes.
felooboolooombaabout 5 hours ago
Yes, but I think it'll back up within a year. It's crazy.
ex-aws-dudeabout 5 hours ago
Question is does the dev sneak in some secret notification code if someone hits it?
aqme28about 5 hours ago
No reason to--no one will hit. You have much much much chance at guessing a random number that solves the next bitcoin block and mining the old fashioned way.
starkeeperabout 4 hours ago
So is this a door-knocking bitcoin robbery game?
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runj__about 4 hours ago
I got a couple of hits by pressing command-R _really_, _really_ fast. But transferring from Nakamoto's wallet feels a bit like fucking with the first bootprints in the lunar regolith.
MattCruikshankabout 4 hours ago
Quick question - why hasn't someone 51 percent attacked Satoshi's wallets?

Estimated cost of a 51% attack on Bitcoin, if no one is cooperating, is $6 billion to $10 billion.

Surely the cost goes down if they get some big players to cooperate.

And the reward is... $83 billion. Basically 10x your money.

I mean, this is the kind of thing that we could sell bonds for, to raise the $6 to $10 billion needed.

Other than the fact that you'd be de-legitimizing BTC, the very thing you're trying to steal. Or morals - them, too. Other than that?

paweldudaabout 4 hours ago
Once these coins as much as budge, price will crater before the transaction has enough confirmations to settle the deposit on any exchange with enough liquidity. Any second on exchange and the hacker is exposed to having his account frozen.

Nobody would buy OTC as they're tainted and it would be basically throwing away their money for something that is traceable and everyone is watching and reacting to further moves

Then the blockchain could be effectively forked to before the attack, invalidating the heist

sansworkabout 4 hours ago
51% attack on bitcoin doesn't let you remove coins from someones wallet it allows you to change which transaction history is considered the real one. So you could send someone bitcoin then do a 51% attack to make the chain without that transaction longest so you get to keep your bitcoin but you can't use it to just take money out of someone elses wallet.
curiousObjectabout 4 hours ago
51% attack allows you to undo a recent transaction (as if it never happened). It does not allow you to change the destination of a transaction or arbitrarily move bitcoins around.
zikduruqeabout 6 hours ago
https://keys.lol is just as fun.
sciencesamaabout 5 hours ago
can use collaborated list to remove the random numbers that failed already.
ivanjermakovabout 5 hours ago
That's gonna be a nice storage bill!
CobrastanJorjiabout 5 hours ago
Let's see...2^241 or so possible 256 bit numbers, so that's 256 * 2^241, so that's....10^50 yottabytes. Obviously we're gonna need cloud storage for all this, so let's say that's about 2 cents per gigabyte/month, so that's...2.2614 × 10^63 dollars per month?

Actually, why does the site list the odds as ~1 in 5.27 × 10⁷²? That's 2^241, but it's picking random 256 bit numbers. Is it because there are so many valid hits?

gumgumpostabout 2 hours ago
Since you're at it, if you're also curious, what would be the energy cost of trying all of them, considering the average power used by a random computer today? Are we looking at something like an average quasar total contained energy?
thaumasiotes38 minutes ago
> Obviously we're gonna need cloud storage for all this

You can keep a comprehensive list of "all 256-bit numbers tried so far" in 256 bits of storage.

logicalleeabout 6 hours ago
This is really fun, I like it a lot. It's great that it's all client-side, real, and does exactly what it says.
fred_is_fredabout 4 hours ago
If you actually won this amount of money it would effectively ruin your life. You and your family would never be safe from a wrench attack - from criminals or a nation-state.
fred_is_fredabout 4 hours ago
Is the search space too big to effectively divide it up GIMPS-style. How do the odds look if every laptop on earth was trying this?
throawayontheabout 3 hours ago
literally the same
SilentM68about 5 hours ago
Hmm, maybe this can help me win the Monopoly Lottery :)
m3kw9about 5 hours ago
Why wouldn't the host just send themselves the key first and then have everyone pull slot machine for them. If you do win it, you are not seeing a penny if you roll from that site.
rokkamokkaabout 5 hours ago
There's no realistic chance it'll be correct anyway
sunrunnerabout 5 hours ago
Not with that attitude it won’t
pixel_poppingabout 5 hours ago
Yeah, people really have no faith.
FajitaNachosabout 5 hours ago
Generally agree that most services like this would at a minimum log a matching key w/ alert. I'm not going to audit the code but maybe OP has good intentions.
jan_Sateabout 6 hours ago
lol. It's fun. Not that I could ever guess it right realistically but it's fun.

This kind of fun thing's exactly why I'm on the internet. Thanks for sharing! :D

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m3kw9about 5 hours ago
what does it mean Loaded 21954 wallets ?
m3kw9about 6 hours ago
maybe some quantum algo can guess every key at once.
throawayontheabout 3 hours ago
not how quantum computing works